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X^2-35X=-36
We move all terms to the left:
X^2-35X-(-36)=0
We add all the numbers together, and all the variables
X^2-35X+36=0
a = 1; b = -35; c = +36;
Δ = b2-4ac
Δ = -352-4·1·36
Δ = 1081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1081}}{2*1}=\frac{35-\sqrt{1081}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1081}}{2*1}=\frac{35+\sqrt{1081}}{2} $
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